Yi Chai
2003-12-01 01:22:34 UTC
It just occured to me that, since I'm using two different (sorta
different) algorithm for PrintEscape (reverse order) and PrintPath
(correct order), my functions MAY give two different paths connection
the starting point and an exiting point.
They do not necessarily have to be the same path in reverse order of
each other, right?
different) algorithm for PrintEscape (reverse order) and PrintPath
(correct order), my functions MAY give two different paths connection
the starting point and an exiting point.
They do not necessarily have to be the same path in reverse order of
each other, right?